numpy.polynomial.legendre.legmulx(c)
[source]
Multiply a Legendre series by x.
Multiply the Legendre series c
by x, where x is the independent variable.
Parameters: |
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Returns: |
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The multiplication uses the recursion relationship for Legendre polynomials in the form
>>> from numpy.polynomial import legendre as L >>> L.legmulx([1,2,3]) array([ 0.66666667, 2.2, 1.33333333, 1.8]) # may vary
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https://docs.scipy.org/doc/numpy-1.17.0/reference/generated/numpy.polynomial.legendre.legmulx.html