numpy.ma.allequal(a, b, fill_value=True)
[source]
Return True if all entries of a and b are equal, using fill_value as a truth value where either or both are masked.
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See also
>>> a = np.ma.array([1e10, 1e-7, 42.0], mask=[0, 0, 1]) >>> a masked_array(data=[10000000000.0, 1e-07, --], mask=[False, False, True], fill_value=1e+20)
>>> b = np.array([1e10, 1e-7, -42.0]) >>> b array([ 1.00000000e+10, 1.00000000e-07, -4.20000000e+01]) >>> np.ma.allequal(a, b, fill_value=False) False >>> np.ma.allequal(a, b) True
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https://docs.scipy.org/doc/numpy-1.17.0/reference/generated/numpy.ma.allequal.html