numpy.char.lstrip(a, chars=None)
For each element in a
, return a copy with the leading characters removed.
Calls str.lstrip
element-wise.
Parameters: |
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Returns: |
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See also
>>> c = np.array(['aAaAaA', ' aA ', 'abBABba']) >>> c array(['aAaAaA', ' aA ', 'abBABba'], dtype='<U7')
The ‘a’ variable is unstripped from c[1] because whitespace leading.
>>> np.char.lstrip(c, 'a') array(['AaAaA', ' aA ', 'bBABba'], dtype='<U7')
>>> np.char.lstrip(c, 'A') # leaves c unchanged array(['aAaAaA', ' aA ', 'abBABba'], dtype='<U7') >>> (np.char.lstrip(c, ' ') == np.char.lstrip(c, '')).all() ... # XXX: is this a regression? This used to return True ... # np.char.lstrip(c,'') does not modify c at all. False >>> (np.char.lstrip(c, ' ') == np.char.lstrip(c, None)).all() True
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https://docs.scipy.org/doc/numpy-1.17.0/reference/generated/numpy.char.lstrip.html