Array.prototype.map
, Array.prototype.filter
, arrow functions, and spread syntax. Obsolete since Gecko 58 (Firefox 58 / Thunderbird 58 / SeaMonkey 2.55)
This feature is obsolete. Although it may still work in some browsers, its use is discouraged since it could be removed at any time. Try to avoid using it.
The array comprehension syntax was a JavaScript expression which allowed you to quickly assemble a new array based on an existing one. However, it has been removed from the standard and the Firefox implementation. Do not use it!
[for (x of iterable) x] [for (x of iterable) if (condition) x] [for (x of iterable) for (y of iterable) x + y]
Inside array comprehensions, these two kinds of components are allowed:
The for-of iteration is always the first component. Multiple for-of iterations or if statements are allowed.
Array comprehension was previously proposed to be standardized in ECMAScript 2016, it provide a useful shortcut for constructing a new array based on the contents of another. Comprehensions can often be used in place of calls to map()
and filter()
, or as a way of combining the two.
The following comprehension takes an array of numbers and creates a new array of the double of each of those numbers.
var numbers = [1, 2, 3, 4]; var doubled = [for (i of numbers) i * 2]; console.log(doubled); // logs 2,4,6,8
This is equivalent to the following map()
operation:
var doubled = numbers.map(i => i * 2);
Comprehensions can also be used to select items that match a particular expression. Here is a comprehension which selects only even numbers:
var numbers = [1, 2, 3, 21, 22, 30]; var evens = [for (i of numbers) if (i % 2 === 0) i]; console.log(evens); // logs 2,22,30
filter()
can be used for the same purpose:
var evens = numbers.filter(i => i % 2 === 0);
map()
and filter()
style operations can be combined into a single array comprehension. Here is one that filters just the even numbers, then creates an array containing their doubles:
var numbers = [1, 2, 3, 21, 22, 30]; var doubledEvens = [for (i of numbers) if (i % 2 === 0) i * 2]; console.log(doubledEvens); // logs 4,44,60
The square brackets of an array comprehension introduce an implicit block for scoping purposes. New variables (such as i in the example) are treated as if they had been declared using let
. This means that they will not be available outside of the comprehension.
The input to an array comprehension does not itself need to be an array; iterators and generators can also be used.
Even strings may be used as input; to achieve the filter and map actions (under Array-like objects) above:
var str = 'abcdef'; var consonantsOnlyStr = [for (c of str) if (!(/[aeiouAEIOU]/).test(c)) c].join(''); // 'bcdf' var interpolatedZeros = [for (c of str) c + '0' ].join(''); // 'a0b0c0d0e0f0'
Again, the input form is not preserved, so we have to use join()
to revert back to a string.
[for (i of [1, 2, 3]) i * i ]; // [1, 4, 9] var abc = ['A', 'B', 'C']; [for (letters of abc) letters.toLowerCase()]; // ["a", "b", "c"]
var years = [1954, 1974, 1990, 2006, 2010, 2014]; [for (year of years) if (year > 2000) year]; // [2006, 2010, 2014] [for (year of years) if (year > 2000) if (year < 2010) year]; // [2006], the same as below: [for (year of years) if (year > 2000 && year < 2010) year]; // [2006]
map
and filter
An easy way to understand array comprehension syntax, is to compare it with the Array map
and filter
methods:
var numbers = [1, 2, 3]; numbers.map(function (i) { return i * i }); numbers.map(i => i * i); [for (i of numbers) i * i]; // all are [1, 4, 9] numbers.filter(function (i) { return i < 3 }); numbers.filter(i => i < 3); [for (i of numbers) if (i < 3) i]; // all are [1, 2]
Using two for-of iterations to work with two arrays:
var numbers = [1, 2, 3]; var letters = ['a', 'b', 'c']; var cross = [for (i of numbers) for (j of letters) i + j]; // ["1a", "1b", "1c", "2a", "2b", "2c", "3a", "3b", "3c"] var grid = [for (i of numbers) [for (j of letters) i + j]]; // [ // ["1a", "1b", "1c"], // ["2a", "2b", "2c"], // ["3a", "3b", "3c"] // ] [for (i of numbers) if (i > 1) for (j of letters) if(j > 'a') i + j] // ["2b", "2c", "3b", "3c"], the same as below: [for (i of numbers) for (j of letters) if (i > 1) if(j > 'a') i + j] // ["2b", "2c", "3b", "3c"] [for (i of numbers) if (i > 1) [for (j of letters) if(j > 'a') i + j]] // [["2b", "2c"], ["3b", "3c"]], not the same as below: [for (i of numbers) [for (j of letters) if (i > 1) if(j > 'a') i + j]] // [[], ["2b", "2c"], ["3b", "3c"]]
Was initially in the ECMAScript 2015 draft, but got removed in revision 27 (August 2014). Please see older revisions of ES2015 for specification semantics.
Desktop | ||||||
---|---|---|---|---|---|---|
Chrome | Edge | Firefox | Internet Explorer | Opera | Safari | |
Basic support | No | No | 30 — 58 | No | No | No |
Mobile | |||||||
---|---|---|---|---|---|---|---|
Android webview | Chrome for Android | Edge Mobile | Firefox for Android | Opera for Android | iOS Safari | Samsung Internet | |
Basic support | No | No | No | 30 — 58 | No | No | No |
Server | |
---|---|
Node.js | |
Basic support | No |
Old comprehensions syntax (do not use anymore!):
[X for (Y in Z)] [X for each (Y in Z)] [X for (Y of Z)]
Differences:
[()=>x for (x of [0, 1, 2])][1]() // 2
[for (x of [0, 1, 2]) ()=>x][1]() // 1, each iteration creates a fresh binding for x.
[i * 2 for (i of numbers)]
[for (i of numbers) i * 2]
if
and for
components.for...of
and not with for...in
iterations.See Bug 1220564, comment 42 for suggestions on updating code.
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Licensed under the Creative Commons Attribution-ShareAlike License v2.5 or later.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Array_comprehensions