The map() method creates a new typed array with the results of calling a provided function on every element in this typed array. This method has the same algorithm as Array.prototype.map(). TypedArray is one of the typed array types here.
typedarray.map(callback[, thisArg])
callbackcurrentValueindexarraymap was called upon.thisArgthis when executing callback.A new typed array.
The map method calls a provided callback function once for each element in a typed array, in order, and constructs a new typed array from the results. callback is invoked only for indexes of the typed array which have assigned values; it is not invoked for indexes that are undefined, those which have been deleted or which have never been assigned values.
callback is invoked with three arguments: the value of the element, the index of the element, and the typed array object being traversed.
If a thisArg parameter is provided to map, it will be passed to callback when invoked, for use as its this value. Otherwise, the value undefined will be passed for use as its this value. The this value ultimately observable by callback is determined according to the usual rules for determining the this seen by a function.
map does not mutate the typed array on which it is called (although callback, if invoked, may do so).
The range of elements processed by map is set before the first invocation of callback. Elements which are appended to the array after the call to map begins will not be visited by callback. If existing elements of the typed array are changed, or deleted, their value as passed to callback will be the value at the time map visits them; elements that are deleted are not visited.
The following code takes a typed array and creates a new typed array containing the square roots of the numbers in the first typed array.
var numbers = new Uint8Array([1, 4, 9]); var roots = numbers.map(Math.sqrt); // roots is now: Uint8Array [1, 2, 3], // numbers is still Uint8Array [1, 4, 9]
The following code shows how map works when a function requiring one argument is used with it. The argument will automatically be assigned to each element of the typed array as map loops through the original typed array.
var numbers = new Uint8Array([1, 4, 9]);
var doubles = numbers.map(function(num) {
return num * 2;
});
// doubles is now Uint8Array [2, 8, 18]
// numbers is still Uint8Array [1, 4, 9]
| Specification | Status | Comment |
|---|---|---|
| ECMAScript 2015 (6th Edition, ECMA-262) The definition of 'TypedArray.prototype.map' in that specification. | Standard | Initial definition. |
| ECMAScript Latest Draft (ECMA-262) The definition of 'TypedArray.prototype.map' in that specification. | Draft |
| Desktop | ||||||
|---|---|---|---|---|---|---|
| Chrome | Edge | Firefox | Internet Explorer | Opera | Safari | |
| Basic support | Yes | 14 | 38 | No | No | No |
| Mobile | |||||||
|---|---|---|---|---|---|---|---|
| Android webview | Chrome for Android | Edge Mobile | Firefox for Android | Opera for Android | iOS Safari | Samsung Internet | |
| Basic support | No | Yes | Yes | 38 | No | No | Yes |
| Server | |
|---|---|
| Node.js | |
| Basic support | 4.0.0 |
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https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/TypedArray/map