const std::type_info& target_type() const noexcept; | (since C++11) |
Returns the type of the stored function.
(none).
typeid(T)
if the stored function has type T
, otherwise typeid(void)
.
#include <functional> #include <iostream> int f(int a) { return -a; } int main() { // fn1 and fn2 have the same type, but their targets do not std::function<int(int)> fn1(f), fn2([](int a) {return -a;}); std::cout << fn1.target_type().name() << '\n' << fn2.target_type().name() << '\n'; }
Possible output:
int (*)(int) main::$_0
obtains a pointer to the stored target (public member function) |
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