Defined in header <type_traits> | ||
---|---|---|
template< class T > struct is_move_assignable; | (1) | (since C++11) |
template< class T > struct is_trivially_move_assignable; | (2) | (since C++11) |
template< class T > struct is_nothrow_move_assignable; | (3) | (since C++11) |
T
is not a referenceable type (i.e., possibly cv-qualified void
or a function type with a cv-qualifier-seq or a ref-qualifier), provides a member constant value
equal to false
. Otherwise, provides a member constant value
equal to std::is_assignable<T&, T&&>::value
.std::is_trivially_assignable<T&, T&&>
std::is_nothrow_assignable<T&, T&&>
T
shall be a complete type, (possibly cv-qualified) void
, or an array of unknown bound. Otherwise, the behavior is undefined.
If an instantiation of a template above depends, directly or indirectly, on an incomplete type, and that instantiation could yield a different result if that type were hypothetically completed, the behavior is undefined.
template< class T > inline constexpr bool is_move_assignable_v = is_move_assignable<T>::value; | (since C++17) | |
template< class T > inline constexpr bool is_trivially_move_assignable_v = is_trivially_move_assignable<T>::value; | (since C++17) | |
template< class T > inline constexpr bool is_nothrow_move_assignable_v = is_nothrow_move_assignable<T>::value; | (since C++17) |
value
[static] | true if T is move-assignable, false otherwise (public static member constant) |
operator bool | converts the object to bool , returns value (public member function) |
operator()
(C++14) | returns value (public member function) |
Type | Definition |
---|---|
value_type | bool |
type | std::integral_constant<bool, value> |
template< class T> struct is_move_assignable : std::is_assignable< typename std::add_lvalue_reference<T>::type, typename std::add_rvalue_reference<T>::type> {}; template< class T> struct is_trivially_move_assignable : std::is_trivially_assignable< typename std::add_lvalue_reference<T>::type, typename std::add_rvalue_reference<T>::type> {}; template< class T> struct is_nothrow_move_assignable : std::is_nothrow_assignable< typename std::add_lvalue_reference<T>::type, typename std::add_rvalue_reference<T>::type> {}; |
The trait std::is_move_assignable
is less strict than MoveAssignable because it does not check the type of the result of the assignment (which, for a MoveAssignable type, must be T&
), nor the semantic requirement that the target's value after the assignment is equivalent to the source's value before the assignment.
The type does not have to implement a move assignment operator in order to satisfy this trait; see MoveAssignable for details.
#include <iostream> #include <string> #include <type_traits> struct Foo { int n; }; struct NoMove { // prevents implicit declaration of default move assignment operator // however, the class is still move-assignable because its // copy assignment operator can bind to an rvalue argument NoMove& operator=(const NoMove&) { return *this; } }; int main() { std::cout << std::boolalpha << "std::string is nothrow move-assignable? " << std::is_nothrow_move_assignable<std::string>::value << '\n' << "int[2] is move-assignable? " << std::is_move_assignable<int[2]>::value << '\n' << "Foo is trivally move-assignable? " << std::is_trivially_move_assignable<Foo>::value << '\n'; std::cout << std::boolalpha << "NoMove is move-assignable? " << std::is_move_assignable<NoMove>::value << '\n' << "NoMove is nothrow move-assignable? " << std::is_nothrow_move_assignable<NoMove>::value << '\n'; }
Output:
std::string is nothrow move-assignable? true int[2] is move-assignable? false Foo is trivially move-assignable? true NoMove is move-assignable? true NoMove is nothrow move-assignable? false
(C++11)(C++11)(C++11) | checks if a type has a assignment operator for a specific argument (class template) |
(C++11)(C++11)(C++11) | checks if a type has a copy assignment operator (class template) |
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