Defined in header <type_traits> | ||
---|---|---|
template< class T > struct is_const; | (since C++11) |
If T
is a const-qualified type (that is, const
, or const volatile
), provides the member constant value
equal true
. For any other type, value
is false
.
T | - | a type to check |
template< class T > inline constexpr bool is_const_v = is_const<T>::value; | (since C++17) |
value
[static] | true if T is a const-qualified type , false otherwise (public static member constant) |
operator bool | converts the object to bool , returns value (public member function) |
operator()
(C++14) | returns value (public member function) |
Type | Definition |
---|---|
value_type | bool |
type | std::integral_constant<bool, value> |
If T
is a reference type then is_const<T>::value
is always false
. The proper way to check a potentially-reference type for const-ness is to remove the reference: is_const<typename remove_reference<T>::type>
.
template<class T> struct is_const : std::false_type {}; template<class T> struct is_const<const T> : std::true_type {}; |
#include <iostream> #include <type_traits> int main() { std::cout << std::boolalpha; std::cout << std::is_const<int>::value << '\n'; // false std::cout << std::is_const<const int>::value << '\n'; // true std::cout << std::is_const<const int*>::value << '\n'; // false std::cout << std::is_const<int* const>::value << '\n'; // true std::cout << std::is_const<const int&>::value << '\n'; // false std::cout << std::is_const<typename std::remove_reference<const int&>::type>::value << '\n'; // true }
Output:
false true false true false true
(C++11) | checks if a type is volatile-qualified (class template) |
(C++17) | obtains a reference to const to its argument (function template) |
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