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std::alignment_of

Defined in header <type_traits>
template< class T >
struct alignment_of;
(since C++11)

Provides the member constant value equal to the alignment requirement of the type T, as if obtained by an alignof expression. If T is an array type, returns the alignment requirements of the element type. If T is a reference type, returns the alignment requirements of the type referred to.

If alignof(T) is not a valid expression, the behavior is undefined.

Helper variable template

template< class T >
inline constexpr std::size_t alignment_of_v = alignment_of<T>::value;
(since C++17)

Inherited from std::integral_constant

Member constants

value
[static]
alignof(T)
(public static member constant)

Member functions

operator std::size_t
converts the object to std::size_t, returns value
(public member function)
operator()
(C++14)
returns value
(public member function)

Member types

Type Definition
value_type std::size_t
type std::integral_constant<std::size_t, value>

Possible implementation

template< class T >
struct alignment_of : std::integral_constant<
                          std::size_t,
                          alignof(T)
                       > {};

Notes

This type trait predates the alignof keyword, which can be used to obtain the same value with less verbosity.

Example

#include <iostream>
#include <type_traits>
 
class A {};
 
int main() 
{
    std::cout << std::alignment_of<A>::value << '\n';
    std::cout << std::alignment_of<int>() << '\n'; // alt syntax
    std::cout << std::alignment_of_v<double> << '\n'; // c++17 alt syntax
}

Output:

1
4
8

See also

alignof operator queries alignment requirements of a type (since C++11)
(C++11)
defines the type suitable for use as uninitialized storage for types of given size
(class template)
(C++11)
defines the type suitable for use as uninitialized storage for all given types
(class template)
(C++11)
trivial type with alignment requirement as great as any other scalar type
(typedef)

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