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std::literals::string_literals::operator""s

Defined in header `<string>`
string operator "" s(const char *str, std::size_t len);	(1)	(since C++14)
u8string operator "" s(const char8_t *str, std::size_t len);	(2)	(since C++20)
u16string operator "" s(const char16_t *str, std::size_t len);	(3)	(since C++14)
u32string operator "" s(const char32_t *str, std::size_t len);	(4)	(since C++14)
wstring operator "" s(const wchar_t *str, std::size_t len);	(5)	(since C++14)

Forms a string literal of the desired type.

1) returns std::string{str, len}

2) returns std::u8string{str, len}

3) returns std::u16string{str, len}

4) returns std::u32string{str, len}

5) returns std::wstring{str, len}

Parameters

str	-	pointer to the beginning of the raw character array literal
len	-	length of the raw character array literal

Return value

The string literal.

Notes

These operators are declared in the namespace std::literals::string_literals, where both literals and string_literals are inline namespaces. Access to these operators can be gained with using namespace std::literals, using namespace std::string_literals, and using namespace std::literals::string_literals.

std::chrono::duration also defines operator""s, to represent literal seconds, but it is an arithmetic literal: 10.0s and 10s are ten seconds, but "10"s is a string.

Example

#include <string>
#include <iostream>
 
int main()
{
    using namespace std::string_literals;
 
    std::string s1 = "abc\0\0def";
    std::string s2 = "abc\0\0def"s;
    std::cout << "s1: " << s1.size() << " \"" << s1 << "\"\n";
    std::cout << "s2: " << s2.size() << " \"" << s2 << "\"\n";
}

Possible output:

s1: 3 "abc"
s2: 8 "abc^@^@def"

std::literals::string_literals::operator""s

Parameters

Return value

Notes

Example

See also