std::chrono::operator ==,!=,<,<=,>,>= (std::chrono::year_month_day_last)
constexpr bool operator==(const std::chrono::year_month_day_last& x,
const std::chrono::year_month_day_last& y) noexcept;
| (1) | (since C++20) |
constexpr bool operator!=(const std::chrono::year_month_day_last& x,
const std::chrono::year_month_day_last& y) noexcept;
| (2) | (since C++20) |
constexpr bool operator< (const std::chrono::year_month_day_last& x,
const std::chrono::year_month_day_last& y) noexcept;
| (3) | (since C++20) |
constexpr bool operator> (const std::chrono::year_month_day_last& x,
const std::chrono::year_month_day_last& y) noexcept;
| (4) | (since C++20) |
constexpr bool operator<=(const std::chrono::year_month_day_last& x,
const std::chrono::year_month_day_last& y) noexcept;
| (5) | (since C++20) |
constexpr bool operator>=(const std::chrono::year_month_day_last& x,
const std::chrono::year_month_day_last& y) noexcept;
| (6) | (since C++20) |
Compares the two year_month_day_last objects x and y. This is a lexicographical comparison: the year() is compared first, then month().
Return value
1) x.year() == y.year() && x.month() == y.month()
2) !(x == y)
3) If x.year() != y.year(), x.year() < y.year(); otherwise, x.month() < y.month().
4) y < x
5) !(y < x)
6) !(x < y)
Notes
If both x and y represent valid dates (x.ok() && y.ok() == true), the result of the lexicographical comparison is consistent with the calendar order.