member only of atomic_ref<Integral> and atomic_ref<Floating> template specializations | ||
T operator+=( T arg ) const noexcept; | (1) | |
member only of atomic_ref<T*> template specialization | ||
T* operator+=( std::ptrdiff_t arg ) const noexcept; | (1) | |
member only of atomic_ref<Integral> and atomic_ref<Floating> template specializations | ||
T operator-=( T arg ) const noexcept; | (1) | |
member only of atomic_ref<T*> template specialization | ||
T* operator-=( std::ptrdiff_t arg ) const noexcept; | (1) | |
member only of atomic_ref<Integral> template specialization | ||
T operator&=( T arg ) const noexcept; | (3) | |
T operator|=( T arg ) const noexcept; | (4) | |
T operator^=( T arg ) const noexcept; | (5) |
Atomically replaces the current value of the referenced object with the result of computation involving the previous value and arg
. These operations are read-modify-write operations.
return fetch_add(arg) + arg;
.return fetch_sub(arg) - arg;
.return fetch_and(arg) & arg;
.return fetch_or(arg) | arg;
.return fetch_xor(arg) ^ arg;
.For signed integral types, arithmetic is defined to use two’s complement representation. There are no undefined results.
For floating-point types, the floating-point environment in effect may be different from the calling thread's floating-point environment. The operation need not be conform to the corresponding std::numeric_limits
traits but is encouraged to do so. If the result is not a representable value for its type, the result is unspecified but the operation otherwise has no undefined behavior.
For T*
types, the result may be an undefined address, but the operations otherwise have no undefined behavior. The program is ill-formed if T
is not an object type.
arg | - | the argument for the arithmetic operation |
The resulting value (that is, the result of applying the corresponding binary operator to the value immediately preceding the effects of the corresponding member function).
Unlike most compound assignment operators, the compound assignment operators for atomic_ref
do not return a reference to their left-hand arguments. They return a copy of the stored value instead.
atomically increments or decrements the referenced object by one (public member function) |
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