Defined in header <fenv.h> | ||
---|---|---|
int feclearexcept( int excepts ); | (since C99) |
Attempts to clear the floating-point exceptions that are listed in the bitmask argument excepts
, which is a bitwise OR of the floating point exception macros.
excepts | - | bitmask listing the exception flags to clear |
0
if all indicated exceptions were successfully cleared or if excepts
is zero. Returns a non-zero value on error.
#include <fenv.h> #include <stdio.h> #include <math.h> #include <float.h> /* * A possible implementation of hypot which makes use of many advanced * floating point features. */ double hypot_demo(double a, double b) { const int range_problem = FE_OVERFLOW | FE_UNDERFLOW; feclearexcept(range_problem); // try a fast algorithm double result = sqrt(a * a + b * b); if (!fetestexcept(range_problem)) // no overflow or underflow return result; // return the fast result // do a more complicated calculation to avoid overflow or underflow int a_exponent,b_exponent; frexp(a, &a_exponent); frexp(b, &b_exponent); if (a_exponent - b_exponent > DBL_MAX_EXP) return fabs(a) + fabs(b); // we can ignore the smaller value // scale so that fabs(a) is near 1 double a_scaled = scalbn(a, -a_exponent); double b_scaled = scalbn(b, -a_exponent); // overflow and underflow is now impossible result = sqrt(a_scaled * a_scaled + b_scaled * b_scaled); // undo scaling return scalbn(result, a_exponent); } int main(void) { // Normal case takes the fast route printf("hypot(%f, %f) = %f\n", 3.0, 4.0, hypot_demo(3.0, 4.0)); // Extreme case takes the slow but more accurate route printf("hypot(%e, %e) = %e\n", DBL_MAX / 2.0, DBL_MAX / 2.0, hypot_demo(DBL_MAX / 2.0, DBL_MAX / 2.0)); return 0; }
Output:
hypot(3.000000, 4.000000) = 5.000000 hypot(8.988466e+307, 8.988466e+307) = 1.271161e+308
(C99) | determines which of the specified floating-point status flags are set (function) |
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