A collection of operators that do not fit into any of the other major categories.
Operator | Operator name | Example | Description |
---|---|---|---|
(...) | function call | f(...) | call the function f(), with zero or more arguments |
, | comma operator | a, b | evaluate expression a, disregard its return value and complete any side-effects, then evaluate expression b, returning the type and the result of this evaluation |
(type) | type cast | (type)a | cast the type of a to type |
? : | conditional operator | a ? b : c | if a is logically true (does not evaluate to zero) then evaluate expression b, otherwise evaluate expression c |
sizeof | sizeof operator | sizeof a | the size in bytes of a |
_Alignof (since C11) | _Alignof operator | _Alignof(type) | the alignment required of type |
The function call expression has the form.
expression ( argument-list(optional) ) |
where.
expression | - | any expression of pointer-to-function type (after lvalue conversions) |
argument-list | - | comma-separated list of expressions (which cannot be comma operators) of any complete object type. May be omitted when calling functions that take no arguments. |
The behavior of the function call expression depends on whether the prototype of the function being called is in scope at the point of call.
Additionally, for every parameter of array type that uses the keyword static between [ and ] , the argument expression must designate a pointer to the element of an array with at least that many elements as specified in the size expression of the parameter. | (since C99) |
va_list
.void f(char* p, int x) {} int main(void) { f("abc", 3.14); // array to pointer and float to int conversions }
void f(); // no prototype int main(void) { f(1, 1.0f); // UB unless f is defined to take an int and a double } void f(int a, double c) {}
The behavior of a function call to a function without a prototype is undefined if.
The evaluations of expression that designates the function to be called and all arguments are unsequenced with respect to each other (but there is a sequence point before the body of the function begins executing).
(*pf[f1()]) (f2(), f3() + f4()); // f1, f2, f3, f4 may be called in any order
Although function call is only defined for pointers to functions, it works with function designators due to the function-to-pointer implicit conversion.
int f(void) { return 1; } int (*pf)(void) = f; int main(void) { f(); // convert f to pointer, then call (&f)(); // create a pointer to function, then call pf(); // call the function (*pf)(); // obtain the function designator, convert to pointer, then calls (****f)(); // convert to pointer, obtain the function, repeat 4x, then call (****pf)(); // also OK }
Functions that ignore unused arguments, such as printf
, must be called with a prototype in scope (the prototype of such functions necessarily uses the trailing ellipsis parameter) to avoid invoking undefined behavior.
A post-C11 defect report DR 427 changes the semantics of preparing function parameters when calling a function with a prototype from assignment to initialization from their corresponding arguments, in order to allow parameters of const-qualified type (which are de-facto allowed). The permitted implicit conversions remain implicit conversions as if by assignment since that's what initialization also uses.
A function call expression where expression consists entirely of an identifier and that identifier is undeclared acts as though the identifier is declared as. extern int identifier(); // returns int and has no prototype So the following complete program is valid C89: main() { int n = atoi("123"); // implicitly declares atoi as int atoi() } | (until C99) |
The comma operator expression has the form.
lhs , rhs |
where.
lhs | - | any expression |
rhs | - | any expression other than another comma operator (in other words, comma operator's associativity is left-to-right) |
First, the left operand, lhs, is evaluated and its result value is discarded.
Then, a sequence point takes place, so that all side effects of lhs are complete.
Then, the right operand, rhs, is evaluated and its result is returned by the comma operator as a non-lvalue.
The type of the lhs may be void
(that is, it may be a call to a function that returns void
, or it can be an expression cast to void
).
The comma operator may be lvalue in C++, but never in C.
The comma operator may return a struct (the only other expressions that return structs are compound literals, function calls, assignments, and the conditional operator).
In the following contexts, the comma operator cannot appear at the top level of an expression because the comma has a different meaning:
If the comma operator has to be used in such context, it must be parenthesized:
// int n = 2,3; // error, comma assumed to begin the next declarator // int a[2] = {1,2,3}; // error: more initializers than elements int n = (2,3), a[2] = {(1,2),3}; // OK f(a, (t=3, t+2), c); // OK, first, stores 3 in t, then calls f with three arguments
Top-level comma operator is also disallowed in array bounds.
// int a[2,3]; // error int a[(2,3)]; // OK, VLA array of size 3 (VLA because (2,3) is not a constant expression)
Comma operator is not allowed in constant expressions, regardless of whether it's on the top level or not.
// static int n = (1,2); // Error: constant expression cannot call the comma operator
See cast operator.
The conditional operator expression has the form.
condition ? expression-true : expression-false |
where.
condition | - | an expression of scalar type |
expression-true | - | the expression that will be evaluated if condition compares unequal to zero |
expression-false | - | the expression that will be evaluated if condition compares equal to zero |
Only the following expressions are allowed as expression-true and expression-false.
NULL
) const int*
and the other is volatile int*
, the result is const volatile int*
), and if the types were different, the pointed-to type is the composite type.#define ICE(x) (sizeof(*(1 ? ((void*)((x) * 0l)) : (int*)1))) // if x is an Integer Constant Expression then macro expands to sizeof( 1 ? NULL : (int *) 1) // (void *)((x)*0l)) -> NULL // according to point (4) this further converts into sizeof(int) // if x is not an Integer Constant Expression then macro expands to // according to point (6) (sizeof(*(void *)(x)) // Error due incomplete type
The conditional operator is never an lvalue expression, although it may return objects of struct/union type. The only other expressions that may return stucts are assignment, comma, function call, and compound literal.
Note that in C++, it may be an lvalue expression.
See operator precedence for the details on the relative precedence of this operator and assignment.
Conditional operator has right-to-left associativity, which allows chaining.
struct vehicle v = arg == 'B' ? bus : arg == 'A' ? airplane : arg == 'T' ? train : arg == 'C' ? car : arg == 'H' ? horse : feet;
See sizeof operator.
See _Alignof operator.
Common operators | ||||||
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assignment | increment decrement | arithmetic | logical | comparison | member access | other |
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